You have two container, a 5 gallon and a 3 gallon container. How do you measure out 4 gallons?
SEE ANSWER
Fill up the 3 gallon container and pour the 3 gallons into the 5 gallon container.Then, fill the 3 gallon container back up, and pour it into the 5 gallon container.The 3 gallon container will have 1 gallon left. Empty the 5 gallon container.Pour the remining 1 gallon into the 5 gallon container.Then fill the 3 gallon container back up and pour it into the 5 gallon container.Thus, you have 4 gallons.
You must keep this thing, its loss will affect your brothers. For once yours is lost, it will soon be lost by others. What is it?
Answer:- Your Temper.
You pick it, You peel the outside, You cook the inside, You eat the outside, And throw away the inside. What is it?
Answer:- An ear of corn.
You want to boil a two-minute egg. If you only have a three-minute timer (hourglass), a four-minute timer and a five-minute timer, how can you boil the egg for only two minutes?
Answer:- Once the water is boiling, turn the three-minute timer and five-minute timer over. When the three-minute timer runs out, put the egg in the boiling water. When the five-minute timer runs out, two minutes have elapsed and it is time take the egg out of the water. You don't need the four-minute timer for this riddle.
You're both in and outside of me; You guide me but don't ride me; I can make a statement with a tongue but no mouth. What am I?
Answer:- Shoes.
You're in a magical bathroom with no windows and the only way things can get in and out is by an open door. You decide to have a bath so you turn on the tap, you shut the door and the handle breaks so you can't open it, you then turn off the tap and the knob breaks so water keeps coming. How do you save yourself from drowning?
Answer:- Pull out the plug in the bath.
You're never too old to learn. What is the contradictory proverb?
Answer:- You can't teach an old dog new tricks.
Your mom has 4 kids, one named North, another called South, and East. What is the last child's name?
Answer:- Your own name, it's your mom, your part of the 4 children!
2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
7+8=?
Solve it?
Answer:- They purchased 100 animals for 100 dollars.
$10 spent to purchase 1 goat.
$45 spent to purchase 9 hens.
$45 spent to purchase 90 chickens.
A bad king has a cellar of 1000 bottles of delightful and very expensive wine. A neighboring queen plots to kill the bad king and sends a servant to poison the wine.
Fortunately (or say unfortunately) the bad king's guards catch the servant after he has only poisoned one bottle.
Alas, the guards don't know which bottle but know that the poison is so strong that even if diluted 100,000 times it would still kill the king. Furthermore, it takes one month to have an effect.
The bad king decides he will get some of the prisoners in his vast dungeons to drink the wine. Being a clever bad king he knows he needs to murder no more than 10 prisoners – believing he can fob off such a low death rate – and will still be able to drink the rest of the wine (999 bottles) at his anniversary party in 5 weeks time.
Explain what is in mind of the king, how will he be able to do so?
Answer:- Three. It seems that it could almost be either, but if you follow the mathematical orders of operation, division is performed before addition. So... half of two is one. Then add two, and the answer is three.
A blind man walks into a hardware store to buy a hammer. There are hammers hanging behind the front desk, but obviously the blind man isn't able to see them. And yet a few minutes later, he happily walks out of the store, having just purchased a new hammer.
How did he do it?
Answer:- He walks up the the front desk where the clerk is working and says "I'd like to buy a hammer."
A boy goes and buys a fishing pole that is 6' 3" long. As he goes to get on the bus, the driver stops him. The driver tells him that he can't take anything longer than 6' onto the bus. The boy goes back into town, purchases one more thing, and the driver allows the boy on the bus. What did the boy buy, and what did he do with it?
Answer:- The boy bought 6' long box. He put the fishing pole in diagonally and the entire package was only 6'!
A cat had three kittens: January, March and May. What was the mother's name.
Answer:- What.
It is stated 'WHAT' was the mother's name.
A deliveryman comes to a house to drop off a package. He asks the woman who lives there how many children she has.
"Three," she says. "And I bet you can't guess their ages."
"Ok, give me a hint," the deliveryman says.
"Well, if you multiply their ages together, you get 36," she says. "And if you add their ages together, the sum is equal to our house number."
The deliveryman looks at the house number nailed to the front of her house. "I need another hint," he says.
The woman thinks for a moment. "My youngest son will have a lot to learn from his older brothers," she says.
The deliveryman's eyes light up and he tells her the ages of her three children. What are their ages?
Answer:- You need to conduct 7 races.
First, separate the horses into 5 groups of 5 horses each, and race the horses in each of these groups. Let's call these groups A, B, C, D and E, and within each group let's label them in the order they finished. So for example, in group A, A1 finished 1st, A2 finished 2nd, A3 finished 3rd, and so on.
We can rule out the bottom two finishers in each race (A4 and A5, B4 and B5, C4 and C5, D4 and D5, and E4 and E5), since we know of at least 3 horses that are faster than them (specifically, the horses that beat them in their respective races).
This table shows our remaining horses:
A1 B1 C1 D1 E1
A2 B2 C2 D2 E2
A3 B3 C3 D3 E3
For our 6th race, let's race the top finishers in each group: A1, B1, C1, D1 and E1. Let's assume that the order of finishers is: A1, B1, C1, D1, E1 (so A1 finished first, E1 finished last).
We now know that horse D1 cannot be in the top 3, because it is slower than C1, B1 and A1 (it lost to them in the 6th race). Thus, D2 and D3 can also not be in the to 3 (since they are slower than D1).
Similarly, E1, E2 and E3 cannot be in the top 3 because they are all slower than D1 (which we already know isn't in the top 3).
Let's look at our updated table, having removed these horses that can't be in the top 3:
A1 B1 C1
A2 B2 C2
A3 B3 C3
We can actually rule out a few more horses. C2 and C3 cannot be in the top 3 because they are both slower than C1 (and thus are also slower than B1 and A1). And B3 also can't be in the top 3 because it is slower than B2 and B1 (and thus is also slower than A1). So let's further update our table:
A1 B1 C1
A2 B2
A3
We actually already know that A1 is our fastest horse (since it directly or indirectly beat all the remaining horses). So now we just need to find the other two fastest horses out of A2, A3, B1, B2 and C1. So for our 7th race, we simply race these 5 horses, and the top two finishers, plus A1, are our 3 fastest horses.